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Question Number 196972 by otchereabdullai@gmail.com last updated on 05/Sep/23

Answered by Frix last updated on 05/Sep/23

$$t=\tan \theta$$$$\frac{2}{t^2+1}(14t^2+9t-14)=0$$$$t=-\frac{9}{28}\pm \frac{\sqrt{865}}{28}$$$$\theta ={\tan }^{-1}\frac{-9+\sqrt{865}}{28}\approx 36.091°$$

Commented by otchereabdullai@gmail.com last updated on 05/Sep/23

$$thanks$$

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