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Question Number 198235 by MASANJAJJ last updated on 15/Oct/23

Answered by Rasheed.Sindhi last updated on 15/Oct/23

$$y=m\mathrm{\angle }B\left[Correspondingangles\right]$$$$x=m\mathrm{\angle }A\left[Alternativeangles\right]$$$$z=m\mathrm{\angle }ACB\left[Sameangles\right]$$$$x+y+z=m\mathrm{\angle }A+m\mathrm{\angle }B+m\mathrm{\angle }ACB=180°\left[Anglesoftriangle\right]$$$$$$

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