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Question Number 200589 by Ikbal last updated on 20/Nov/23

Answered by Frix last updated on 20/Nov/23

$$\mathrm{First}\mathrm{try}\mathrm{factors}\mathrm{of}\pm 40\Rightarrow$$$$x^4-3x^2-42x-40=$$$$=(x+1)(x-4)(x^2+3x+10)$$$$\Rightarrow$$$$x=-1\vee x=4\vee x=-\frac{3}{2}\pm \frac{\sqrt{31}}{2}\mathrm{i}$$

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