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Question Number 200970 by Mastermind last updated on 27/Nov/23

	Answered by JDamian last updated on 27/Nov/23

	$R e a l l y ?$
	Answered by mr W last updated on 27/Nov/23

	$\frac{4 x^{2}}{2 x - 1} = \frac{1 + {(2 x)}^{2} - 1}{2 x - 1} = \frac{1}{2 x - 1} + (2 x + 1)$ $\Rightarrow A = 2 x + 1$
	Answered by Rasheed.Sindhi last updated on 28/Nov/23

	$\frac{4 x^{2}}{2 x - 1} = \frac{1}{2 x - 1} + A \Rightarrow A = \frac{4 x^{2}}{2 x - 1} - \frac{1}{2 x - 1}$ $\Rightarrow A = \frac{4 x^{2} - 1}{2 x - 1} = \frac{(2 x + 1) (2 x - 1)}{(2 x - 1)} = 2 x + 1$
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