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Question Number 203219 by hardmath last updated on 12/Jan/24

Answered by witcher3 last updated on 15/Jan/24

$$\mathrm{evident}$$$${(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d})}^2={\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2+{\mathrm{d}}^2+2(\mathrm{ab}+\mathrm{bc}+\mathrm{cd}+\mathrm{da})$$$$\mathrm{since}\mathrm{a},\mathrm{b},\mathrm{c},\mathrm{d}⩾0$$$${(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d})}^2⩾{\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2+{\mathrm{d}}^2$$

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