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Question Number 203688 by ajfour last updated on 26/Jan/24

Commented by ajfour last updated on 26/Jan/24

Repost   Q.203636

RepostQ.203636

Commented by ajfour last updated on 26/Jan/24

Looks suuperB!  waiting for you to  elaborate, gracious.

LookssuuperB!waitingforyoutoelaborate,gracious.

Commented by mr W last updated on 27/Jan/24

i think i got it, easier than i thought,  (T_A /(mg))=(a/( [(((1/3)(√((((a^2 +b^2 +c^2 )^2 )/4)+(μ^4 /9)))+((a^2 +b^2 +c^2 )/6)))^(1/3) −(((1/3)(√((((a^2 +b^2 +c^2 )^2 )/4)+(μ^4 /9)))−((a^2 +b^2 +c^2 )/6)))^(1/3) ]^(3/2) ))  with μ=(√((kQ^2 )/(mg)))  i hope you may comfirm this.

ithinkigotit,easierthanithought,TAmg=a[13(a2+b2+c2)24+μ49+a2+b2+c26313(a2+b2+c2)24+μ49a2+b2+c263]32withμ=kQ2mgihopeyoumaycomfirmthis.

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