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Question Number 204921 by mathlove last updated on 02/Mar/24

Answered by Frix last updated on 02/Mar/24

$$\underset{0}{\stackrel{1}{\int }}\frac{dx}{\sqrt{x+3}+\sqrt{x+1}}=\frac{1}{2}\underset{0}{\stackrel{1}{\int }}\sqrt{x+3}-\sqrt{x+1}dx=$$$$={\left[\frac{{(x+3)}^{\frac{3}{2}}-{(x+1)}^{\frac{3}{2}}}{3}\right]}_0^1=3-\frac{2\sqrt{2}}{3}-\sqrt{3}$$$$2a+3b-4c=8$$

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