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Question Number 205204 by BaliramKumar last updated on 12/Mar/24

	Answered by A5T last updated on 12/Mar/24

	$C o n t a i n e r A : S p i r i t (35 l), W a t e r (45 l)$ $C o n t a i n e r B : S p i r i t (\frac{7}{16} \times 20 = 8.75), W a t e r (11.25)$ $\Rightarrow C o n t a i n e r A^{'} : S p i r i t (26.25 l), W a t e r (33.75 l)$ $C o n t a i n e r A^{″} : S p i r i t (26.25 l), W a t e r (53.75 l)$ $S : W = 21 : 43$ $C o n t a i n e r B^{'} : S p i r i t (8.75 + \frac{21}{64} \times 32), W a t e r (11.25 + \frac{43}{64} \times 32)$ $= S p i r i t (19.25 l), W a t e r (32.75 l)$ $\Rightarrow W : S = 32.75 : 19.25 = 131 : 77$
	Commented by BaliramKumar last updated on 12/Mar/24

	$thanks sir$ $any short solution$
	Commented by A5T last updated on 12/Mar/24

	$S p i r i t : (0 + \frac{7}{16} \times 20 + \frac{21}{64} \times 32 = 19.25 l);$ $W a t e r : (0 + \frac{9}{16} \times 20 + \frac{43}{64} \times 32 = 32.75 l)$
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