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Question Number 20558 by khamizan833@gmail.com last updated on 28/Aug/17

Commented by ajfour last updated on 28/Aug/17

full form of cot x is cotangent x.

fullformofcotxiscotangentx.

Answered by Tinkutara last updated on 28/Aug/17

(1−cot 22°)(1−cot 23°)=1−cot 23°−  cot 22°+cot 22°cot 23°  cot 45°=((cot 22°cot 23°−1)/(cot 22°+cot 23°))=1  ⇒cot 22°cot 23°−cot 22°−cot 23°=1  ∴(1−cot 22°)(1−cot 23°)=2

(1cot22°)(1cot23°)=1cot23°cot22°+cot22°cot23°cot45°=cot22°cot23°1cot22°+cot23°=1cot22°cot23°cot22°cot23°=1(1cot22°)(1cot23°)=2

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