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Question Number 206136 by cortano21 last updated on 07/Apr/24
Answered by A5T last updated on 07/Apr/24
f(f(f(f(x))))=[f(x)]2−3[f(x)]+4=f(x2−3x+4)[f(2)]2−3[f(2)]+4=f(2)⇒[f(2)]2−4f(2)+4=0[f(2)−2]2=0⇒f(2)=2
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