Question and Answers Forum

All Questions      Topic List

Relation and Functions Questions

Previous in All Question      Next in All Question      

Previous in Relation and Functions      Next in Relation and Functions      

Question Number 206136 by cortano21 last updated on 07/Apr/24

Answered by A5T last updated on 07/Apr/24

f(f(f(f(x))))=[f(x)]^2 −3[f(x)]+4=f(x^2 −3x+4)  [f(2)]^2 −3[f(2)]+4=f(2)⇒[f(2)]^2 −4f(2)+4=0  [f(2)−2]^2 =0⇒f(2)=2

f(f(f(f(x))))=[f(x)]23[f(x)]+4=f(x23x+4)[f(2)]23[f(2)]+4=f(2)[f(2)]24f(2)+4=0[f(2)2]2=0f(2)=2

Terms of Service

Privacy Policy

Contact: info@tinkutara.com