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Question Number 206558 by luciferit last updated on 18/Apr/24

Answered by Frix last updated on 18/Apr/24

$$\int \sqrt{3+5\sqrt{x}}dx\stackrel{t=\sqrt{3+5\sqrt{x}}}{=}$$$$=\frac{4}{25}\int (t^4-3t^2)dt=\frac{4}{25}(\frac{t^5}{5}-t^3)=$$$$=\frac{4(25x+5\sqrt{x}-6)\sqrt{3+5\sqrt{x}}}{125}+C$$

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