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Question Number 206729 by mr W last updated on 23/Apr/24

Answered by A5T last updated on 23/Apr/24

$$\frac{sin84}{AD}=\frac{sin54}{AC}\Rightarrow AD=\frac{ACsin84}{sin54}...\left(i\right)$$$$\frac{sin(?)}{AD}=\frac{sin(54-?)}{BD=AC}\Rightarrow AD=\frac{ACsin(?)}{sin(54-?)}...\left(ii\right)$$$$\left(i\right)\mathrm{\&}\left(ii\right)\Rightarrow \frac{sin84}{sin54}=\frac{sin(?)}{sin(54-?)}\Rightarrow ?=30°$$

Commented by mr W last updated on 23/Apr/24

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