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Question Number 20823 by ANTARES_VY last updated on 04/Sep/17

Answered by ajfour last updated on 04/Sep/17

$$2y+5\left(\frac{x-9}{2}\right)=5$$$$\Rightarrow 4y+5x=55...\left(i\right)$$$$and4x-y=11]\times 4$$$$so\{\begin{array}{l}16x-4y=44\\ 4y+5x=55\end{array}$$$$\Rightarrow 21x=99$$$$x=\frac{33}{7},andy=4x-11$$$$\Rightarrow y=\frac{4\times 33}{7}-11=\frac{132-77}{7}$$$$y=\frac{55}{7};andz=\frac{x-9}{2}$$$$\Rightarrow z=\frac{1}{2}(\frac{33}{7}-9)=-\frac{15}{7}$$$$soy+z-x=\frac{55-15-33}{7}=1.$$

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