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Question Number 208855 by efronzo1 last updated on 25/Jun/24

Answered by mr W last updated on 25/Jun/24

let t=1+∣x∣≥1  ((2024^(−t) −λ)/(2024^(−t) −λ^(−1) ))=λ 2024^t   2024^(−t) −λ=λ−2024^t   2λ=2024^(−t) +2024^t =2024^t (1+(1/(2024^(2t) )))>2024  ⇒λ>1012  ⇒∣λ∣_(min) =1013

lett=1+x∣⩾12024tλ2024tλ1=λ2024t2024tλ=λ2024t2λ=2024t+2024t=2024t(1+120242t)>2024λ>1012⇒∣λmin=1013

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