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Question Number 208931 by byaw last updated on 27/Jun/24

Answered by mr W last updated on 27/Jun/24

(a)  R=m(g+a)=0.5×(10+2)=6 N    (b)(i)  Mg×0.8+100×0.3+80×1.3−90×2.4=0  ⇒M=10.25 kg  (b)(ii)  R_B =102.5+100+80−90=192.5 N

(a)R=m(g+a)=0.5×(10+2)=6N(b)(i)Mg×0.8+100×0.3+80×1.390×2.4=0M=10.25kg(b)(ii)RB=102.5+100+8090=192.5N

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