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Question Number 208943 by MWSuSon last updated on 28/Jun/24

Answered by A5T last updated on 28/Jun/24

a. (([ADM])/([ABCD]))=(((1/2)×AD×DM)/(AD×(DM×2)))=(1/4)  b. Let AM and DN intersect at E  (([DEM])/([ABCD]))=(((1/2)×((AD)/2)×DM)/(AD×DM×2))=(1/8)  c. 1−(1/4)−(1/8)=(5/8)

a.[ADM][ABCD]=12×AD×DMAD×(DM×2)=14b.LetAMandDNintersectatE[DEM][ABCD]=12×AD2×DMAD×DM×2=18c.11418=58

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