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Question Number 209358 by peter frank last updated on 08/Jul/24

Commented by mr W last updated on 08/Jul/24

$$ifthebowlissmooth,whyshouldthe$$$$smallblockrotatewiththebowland$$$$notfalltothemiddleofthebowl?$$

Commented by mr W last updated on 08/Jul/24

$$theanswer\sqrt{\frac{g\cos \theta }{R}}shouldbe$$$$\sqrt{\frac{g}{R\cos \theta }}$$

Commented by mr W last updated on 08/Jul/24

$$whatabookareyouworkingwith?$$$$itcontainstoomanymistakes!$$

Answered by mr W last updated on 08/Jul/24

Commented by mr W last updated on 08/Jul/24

$$mg\tan \theta =m\left(R\sin \theta \right){\omega }^2$$$$\Rightarrow \omega =\sqrt{\frac{g}{R\cos \theta }}$$

Commented by peter frank last updated on 08/Jul/24

$$\mathrm{thank}\mathrm{you}\mathrm{for}\mathrm{the}\mathrm{solution}.$$

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