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Question Number 209415 by RoseAli last updated on 09/Jul/24

Commented by Frix last updated on 09/Jul/24

$$\mathrm{This}\mathrm{is}\mathrm{just}\mathrm{a}\mathrm{term}.$$$$\mathrm{No}\mathrm{question}\Rightarrow \mathrm{No}\mathrm{answer}$$$$$$$${\mathrm{It}}^{\prime }\mathrm{s}\mathrm{like}\mathrm{these}:$$$$\bullet 5{ab}^2+7c-3$$$$\bullet 97.3\mathrm{km}/\mathrm{hr}$$$$\bullet \mathrm{A}\mathrm{bird}\mathrm{in}\mathrm{a}\mathrm{tree}.$$

Answered by lepuissantcedricjunior last updated on 09/Jul/24

$${\mathit{x}}^8+98{\mathit{x}}^4+1=0$$$$\mathit{p}\mathit{o}\mathit{s}\mathit{o}\mathit{n}\mathit{s}{\mathit{x}}^4=\mathit{t}=>{\mathit{x}}^8={\mathit{t}}^2$$$${\mathit{t}}^2+98\mathit{t}+1=0$$$$\mathbf{\Delta }={98}^2-4=(98-4)(98+4)=94\times 102$$$$\mathit{t}=\frac{-98\pm \sqrt{94\times 102}}{2}$$$${\mathit{x}}^4=\mathit{t}=\frac{-98+\sqrt{{98}^2(1-{\left(\frac{1}{49}\right)}^2)}}{2}$$$$\mathit{x}=\sqrt[4]{7^2(-1+\sqrt{1-\frac{1}{{49}^2}})=\sqrt{7}\sqrt[4]{\frac{1}{7}\sqrt{{49}^2-1}}-1}$$

Commented by mr W last updated on 09/Jul/24

$$wrong!$$$$\mathrm{\Delta }={98}^2-4=(98-2)(98+2)=96\times 100=9600$$

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