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Question Number 209846 by peter frank last updated on 23/Jul/24

Answered by mr W last updated on 23/Jul/24

$$theresultistoolarge.$$$$20\times (15-10)\times 12\times {10}^{-6}=0.0012m$$$$=1.2mm$$$$\Rightarrow theerroris1.2mm.$$

Commented by peter frank last updated on 23/Jul/24

$$\mathrm{thank}\mathrm{you}$$

Answered by Spillover last updated on 23/Jul/24

$$\alpha =\frac{△L}{L△\theta }$$$$Error=△L$$$$\alpha =\frac{△L}{L△\theta }$$$$△L=\alpha L△\theta =\alpha L({\theta }_1-{\theta }_0)$$$${\theta }_1={15}^{°}C=288K$$$${\theta }_0={10}^{°}C=283K$$$$△L=\alpha L△\theta =\alpha L({\theta }_1-{\theta }_0)$$$$△L=\alpha L({\theta }_1-{\theta }_0)=12\times {10}^{-6}\times 20\times 5=0.12cm$$$$△L=0.12cm=1.2mm\left(Toolarge\right)$$$$$$

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