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Question Number 210318 by peter frank last updated on 06/Aug/24

Commented by mr W last updated on 06/Aug/24

$w h a t s h o u l d b e r e a c h e d w i t h t h e$ $s i n g l e t u b e w h e n i t r e p l a c e s t h e t h r e e$ $o n e s ? t h e s a m e f l o w r a t e w i t h t h e$ $s i n g l e t u b e a s w i t h t h e t h r e e t u b e s ?$
	Answered by mr W last updated on 06/Aug/24

	Commented by mr W last updated on 06/Aug/24

	$H = 30 c m$ $h_{1} = 0$ $h_{2} = 4 c m$ $h_{3} = 8 c m$ $L_{1} = 39 c m$
	Commented by mr W last updated on 06/Aug/24

	Commented by peter frank last updated on 07/Aug/24

	$thank you Mr W$
	Answered by BHOOPENDRA last updated on 06/Aug/24

	$L e t s a y s i n g l e t u b e f l o w o f r a t e i s Q$ $a n d t h e l e n g t h o f t u b e i s L^{'}$ $r e s t o f t h i n g s y o u c a n s e e f r o m a b o v e f i g . M r . W$ $h a s p r o v i d e d t h e f i g u r e .$ $t o t a l f l o w Q = Q_{1} + Q_{2} + Q_{3}$ $w h e r e Q_{1}, Q_{2}, Q_{3} f l o w o f t u b e$ $r e s p e c t i v l y .$ $Q = Q_{1} + Q_{2} + Q_{3}$ $\frac{30}{L^{'}} = \frac{30}{l_{1}} + \frac{26}{l_{1}} + \frac{22}{l_{1}}$ $\frac{30}{L^{'}} = \frac{78}{39}$ $L^{'} = 15 c m$ $N o t e - P (p r e s s u r e) = ρ g h$ $R a t e o f f l o w Q = \frac{π Δ {P r}^{4}}{8 η l}$
	Commented by peter frank last updated on 07/Aug/24

	$thank you$
	Answered by Spillover last updated on 06/Aug/24

	Commented by peter frank last updated on 07/Aug/24

	$thank you$
	Answered by Spillover last updated on 06/Aug/24

	Commented by peter frank last updated on 07/Aug/24

	$thank you$
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