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Question Number 210754 by mokys last updated on 18/Aug/24
Answered by Berbere last updated on 19/Aug/24
1+Nr∼Nrlimn→∞∑Nk=1ksNs=limN→∞∑Nk=11N(kN)s=∫01xs=1s+1=r−sr1=r−ss+1=rlimN→∞∑Nk=1ks1+−Nr=limN→∞Nr1+−Nr.1+....+NsNs=+−.r−srlimx→∞1+−xrxr=+−1
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