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Question Number 211365 by JuniorKepler last updated on 06/Sep/24

Answered by mr W last updated on 07/Sep/24

$$\frac{{(x+y)}^p{(x+y)}^q}{x^p{y}^q}=1$$$${(1+\frac{y}{x})}^p{(1+\frac{x}{y})}^q=1$$$$sayy=kx$$$${(1+k)}^p{(1+\frac{1}{k})}^q=1\Rightarrow {(1+k)}^{p+q}-k^q=0$$$$\Rightarrow k=constantw.r.t.x$$$$\Rightarrow \frac{dy}{dx}=k\Rightarrow \frac{d^{2}y}{{dx}^2}=0$$$$\Rightarrow answer\left(a\right)$$

Answered by MATHEMATICSAM last updated on 07/Sep/24

$$0$$

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