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Question Number 212784 by Spillover last updated on 23/Oct/24

Answered by A5T last updated on 24/Oct/24

d^2 =(r−a)^2 +r^2 −2r(r−a)cosθ c^2 =(r−a)^2 +r^2 +2r(r−a)cosθ ⇒c^2 +d^2 =2(r−a)^2 +2r^2 =4r^2 +2a^2 −4ar b=(2r−a) ⇒a^2 +b^2 =a^2 +4r^2 +a^2 −4ar=4r^2 +2a^2 −4ar ⇒a^2 +b^2 =c^2 +d^2

d2=(r−a)2+r2−2r(r−a)cosθc2=(r−a)2+r2+2r(r−a)cosθ⇒c2+d2=2(r−a)2+2r2=4r2+2a2−4arb=(2r−a)⇒a2+b2=a2+4r2+a2−4ar=4r2+2a2−4ar⇒a2+b2=c2+d2

Commented by Spillover last updated on 24/Oct/24

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