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Question Number 212801 by Spillover last updated on 24/Oct/24

Answered by som(math1967) last updated on 24/Oct/24

Commented by som(math1967) last updated on 24/Oct/24

((OL)/(PL))=tan 22(1/2)  PL=6((√2)+1)  PL=PM=6((√2)+1)   ((MN)/(PM))=tan 30  MN=((6((√2)+1))/( (√3)))  ∴ R=((6((√2)+1))/( (√3)))

OLPL=tan2212PL=6(2+1)PL=PM=6(2+1)MNPM=tan30MN=6(2+1)3R=6(2+1)3

Answered by mr W last updated on 24/Oct/24

(R/(tan ((60°)/2)))=(6/(tan ((45°)/2)))  ⇒R=((2(√3))/( (√2)−1))=2(√3)((√2)+1)

Rtan60°2=6tan45°2R=2321=23(2+1)

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