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Question Number 213550 by mr W last updated on 08/Nov/24

Commented by mr W last updated on 08/Nov/24

semicircle

semicircle

Answered by A5T last updated on 08/Nov/24

Commented by A5T last updated on 08/Nov/24

((s−3)/2)=r−3⇒s=2r−3 ((t−6)/2)=r−6⇒t=2r−6 (t−6)^2 +(s−3)^2 =(2r)^2 =4r^2 ⇒(2r−12)^2 +(2r−6)^2 =4r^2 ⇒r^2 −18r+45=0⇒r=3 or 15 t−6>0⇒r=15⇒2r=30

s−32=r−3⇒s=2r−3t−62=r−6⇒t=2r−6(t−6)2+(s−3)2=(2r)2=4r2⇒(2r−12)2+(2r−6)2=4r2⇒r2−18r+45=0⇒r=3or15t−6>0⇒r=15⇒2r=30

Commented by mr W last updated on 08/Nov/24

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Answered by Spillover last updated on 09/Nov/24

R²=[R -6]²+ [R -3]² R² -12R +36 + R² -6R +9 R²=2R² -18R +45 R² -18R +45=0 R=[18+[324 - 180]½]/2 R=[18+12]/2=15 EF=[15+15]=30

R²=[R -6]²+ [R -3]² R² -12R +36 + R² -6R +9 R²=2R² -18R +45 R² -18R +45=0 R=[18+[324 - 180]½]/2 R=[18+12]/2=15 EF=[15+15]=30

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