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Question Number 213556 by ajfour last updated on 08/Nov/24

Commented by ajfour last updated on 08/Nov/24

$F i n d r a d i u s .$
	Answered by A5T last updated on 08/Nov/24

	$\frac{a b c}{4 R} = \frac{a b s i n α}{2} \Rightarrow R = \frac{c}{2 s i n α} [c = \sqrt{a^{2} + b^{2} - 2 a b c o s α}]$ $\Rightarrow R = \frac{\sqrt{a^{2} + b^{2} - 2 a b c o s α}}{s i n α}$
	Answered by mr W last updated on 08/Nov/24

	$c = \sqrt{a^{2} + b^{2} - 2 a b \cos α}$ $R = \frac{c}{2 \sin C} = \frac{\sqrt{a^{2} + b^{2} - 2 a b \cos α}}{2 \sin α} ✓$
	Commented by ajfour last updated on 08/Nov/24

	$t o o g o o d!$
	Answered by Spillover last updated on 09/Nov/24

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