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Question Number 213835 by BaliramKumar last updated on 18/Nov/24

Answered by mehdee7396 last updated on 18/Nov/24

OA=(√(13))  &   OB=3  sin(θ/2)=(3/( (√(13))))⇒cos(θ/2)=(2/( (√(13))))  ⇒tan(θ/2)=(3/2)⇒θ=2tan^(−1) (3/2)  ✓

OA=13&OB=3sinθ2=313cosθ2=213tanθ2=32θ=2tan132

Commented by mehdee7396 last updated on 18/Nov/24

Commented by BaliramKumar last updated on 18/Nov/24

thanks

thanks

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