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Question Number 213861 by BaliramKumar last updated on 19/Nov/24

Answered by A5T last updated on 19/Nov/24

$$cotA+cotB=\frac{1}{tanA}+\frac{1}{tanB}=\frac{p}{tanAtanB}=q$$$$\Rightarrow tanAtanB=\frac{p}{q}$$$$cot(A+B)=\frac{1}{tan(A+B)}=\frac{1-tanAtanB}{tanA+tanB}=\frac{1-\frac{p}{q}}{p}$$$$\Rightarrow cot(A+B)=\frac{q-p}{pq}$$

Commented by BaliramKumar last updated on 19/Nov/24

$$Thanks$$

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