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Question Number 21580 by ketto last updated on 28/Sep/17

Answered by Joel577 last updated on 29/Sep/17

$$\mathrm{Because}A\mathrm{and}B\mathrm{mutually}\mathrm{exclusive},\mathrm{then}$$$$P(A\cap B)=0$$$$\mathrm{and}$$$$P(A\cup B)=1$$$$$$$$P(A\cup B)=P\left(A\right)+P\left(B\right)-P(A\cap B)$$$$1=\frac{3}{7}+P\left(B\right)-0$$$$P\left(B\right)=\frac{4}{7}$$

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