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Question Number 21662 by x² - y²@gmail.com last updated on 30/Sep/17

Answered by Joel577 last updated on 30/Sep/17

I = ∫ ((8x^5 − 18x^3 )/(2x^3 − 3x^2 )) dx = ∫ ((2x^3 (4x^2 − 9))/(x^2 (2x − 3))) dx = ∫ ((2x(2x + 3)(2x − 3))/(2x − 3)) dx = ∫ 4x^2 + 6x dx = (4/3)x^3 + 3x^2 + C

I=∫8x5−18x32x3−3x2dx=∫2x3(4x2−9)x2(2x−3)dx=∫2x(2x+3)(2x−3)2x−3dx=∫4x2+6xdx=43x3+3x2+C

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