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Question Number 216703 by LMKhit last updated on 16/Feb/25

Answered by issac last updated on 16/Feb/25

(√(1−x^2 ))=((√π)/2)Σ_(h=0) ^∞ (((−1)^h )/(h!((1/2)−h)!))x^(2h) , ∣x∣≤1 because r=lim_(n→∞) inf∣ (a_(n+1) /a_n ) ∣≤1

1−x2=π2∑∞h=0(−1)hh!(12−h)!x2h,∣x∣≤1becauser=liminfn→∞∣an+1an∣≤1

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