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Question Number 217617 by chidera last updated on 16/Mar/25

Answered by som(math1967) last updated on 17/Mar/25

$$Probabilityapointlies△ADM$$$$=\frac{Ar△ADM}{ABCD}=\frac{1}{4}$$$$△ADMbutnot△ADN$$$$=\frac{△DOM}{ABCD}=\frac{1}{8}$$$$neither△ADMnor△ADN$$$$=\frac{ArMONBC}{ABCD}=1-\frac{3}{8}=\frac{5}{8}$$

Commented by som(math1967) last updated on 17/Mar/25

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