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Question Number 218366 by Mingma last updated on 08/Apr/25

Commented by Mingma last updated on 08/Apr/25

Find the dimensions

Commented by zetamaths last updated on 08/Apr/25

the dimension is 2  ⇔dim(W)=2 because    a+b+c=0  a=−b−c    Or (a;b;c)  (−b−c;b;c)⇔(−b;b;0)+(−c;0;c)  b(−1;1;0)+c(−1;0;1)  W=Vect_K ((−1;1;0);(−1;0;1))=<(−1;1;0);(−1;0;1)>_K   finaly  ⇔dim(W)=2

thedimensionis2dim(W)=2becausea+b+c=0a=bcOr(a;b;c)(bc;b;c)(b;b;0)+(c;0;c)b(1;1;0)+c(1;0;1)W=VectK((1;1;0);(1;0;1))=<(1;1;0);(1;0;1)>Kfinalydim(W)=2

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