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Question Number 218410 by Spillover last updated on 09/Apr/25
Answered by Nicholas666 last updated on 09/Apr/25
given;AB,CDtangentstocircleO:MmidpointofBC;AD∣∣BC;BD=x,AB=y,CD=zprovex2=y.zsolution∗AD∣∣BC∠ABD=∠DBC(alternateinteriorangles)∗∠ABD=∠BDC(anglebetweentangentandchord)∗ABD∼△BDC(AA:∠ABD=∠DBC,∠ABD=∠BDC)∗ratioofcorrespondingsides;AB/BD=BD/CD∗y/x=x/z=y.z=x.x=y.z=x2∗cross−multiply:x2=y.zq.e.d
Answered by Spillover last updated on 10/Apr/25
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