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Question Number 218525 by Spillover last updated on 11/Apr/25

Answered by mr W last updated on 11/Apr/25

Commented by mr W last updated on 11/Apr/25

$$\tan \theta =\frac{1}{2}$$$$3\times 1\tan \theta =1+2\times 1\tan \alpha$$$$\Rightarrow \tan \alpha =\frac{1}{4}\Rightarrow \sin \alpha =\frac{1}{\sqrt{17}},\cos \alpha =\frac{4}{\sqrt{17}}$$$$A_{blue}=3\times 1^2+8\times \frac{1^2\times \sin \alpha \cos \alpha }{2}$$$$=3+4\times \frac{1}{\sqrt{17}}\times \frac{4}{\sqrt{17}}=\frac{67}{17}$$

Commented by Spillover last updated on 17/Apr/25

$$greatthankyou$$

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