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Question Number 218738 by Spillover last updated on 14/Apr/25

Answered by som(math1967) last updated on 15/Apr/25

Commented by som(math1967) last updated on 15/Apr/25

$$area△ABC=\frac{1}{2}\times a\times b\times sinA$$$$area△ABC=\frac{1}{2}\times h\times BC$$$$\therefore \frac{1}{2}\times ab\times sinA=\frac{1}{2}\times h\times 2RsinA$$$$[\because BC=2RSinA]$$$$\therefore ab=2Rh$$

Commented by Spillover last updated on 15/Apr/25

$$thanks$$

Answered by Spillover last updated on 15/Apr/25

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