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Question Number 218844 by Spillover last updated on 16/Apr/25

	Answered by som(math1967) last updated on 16/Apr/25

	$l e t l e n t h o f r e c t a n g l e = l, w i d t h = b$ $2 l + 6 b = 4 l + 2 b = s i d e o f s q u a r e$ $\Rightarrow 4 b = 2 l \Rightarrow l = 2 b$ $l \times b = 18 \Rightarrow 2 b^{2} = 18 \Rightarrow b = 3, l = 6$ $s i d e o f s q u a r e = 2 \times 6 + 6 \times 3 = 30 c m$ $a r e a o f s q u a r e = 900 {c m}^{2}$ $a r e a 24 r e c t a n g l e s = 24 \times 18 = 432 {c m}^{2}$ $b l u e a r e a = 900 - 432 = 468 {c m}^{2}$
	Answered by Spillover last updated on 16/Apr/25

	Answered by Spillover last updated on 16/Apr/25

	Answered by Spillover last updated on 16/Apr/25

	Answered by Spillover last updated on 16/Apr/25

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