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Question Number 219403 by ea last updated on 23/Apr/25

Answered by mr W last updated on 24/Apr/25

Commented by mr W last updated on 24/Apr/25

$$4x^2=2b^2+2y^2-4d^2$$$$4y^2=2x^2+2c^2-4d^2$$$$\mathrm{\Sigma }:$$$$x^2+y^2+4d^2=b^2+c^2$$$$\mid AX{\mid }^2+\mid AY{\mid }^2+4\mid XY{\mid }^2=\mid AB{\mid }^2+\mid AC{\mid }^2$$

Commented by ea last updated on 24/Apr/25

Perfect sir!

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