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Question Number 21964 by chernoaguero@gmail.com last updated on 07/Oct/17

Answered by ibraheem160 last updated on 07/Oct/17

$$\mathrm{y}={\mathrm{x}}^2{(2\mathrm{x}-5)}^4$$$$\frac{\mathrm{du}}{\mathrm{dx}}=2\mathrm{x},\frac{\mathrm{dv}}{\mathrm{dx}}=8{(2\mathrm{x}-5)}^3$$$$$$$$\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{u}\frac{\mathrm{dv}}{\mathrm{dx}}+\mathrm{v}\frac{\mathrm{du}}{\mathrm{dx}}$$$$\Rightarrow {\mathrm{x}}^2.8{(2\mathrm{x}-5)}^3+2\mathrm{x}{(2\mathrm{x}-5)}^4$$$$\Rightarrow {8\mathrm{x}}^2{(2\mathrm{x}-5)}^3+2\mathrm{x}{(2\mathrm{x}-5)}^4$$$$=2\mathrm{x}{(2\mathrm{x}-5)}^3(6\mathrm{x}-5)$$

Commented by chernoaguero@gmail.com last updated on 08/Oct/17

$$\mathrm{Thank}\mathrm{you}\mathrm{sir}$$

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