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Question Number 22475 by mondodotto@gmail.com last updated on 19/Oct/17

Commented by Rasheed.Sindhi last updated on 19/Oct/17

$$\left(\mathrm{b}\right)9^{{8\mathrm{x}}^2}$$$$\sqrt{9^{{16\mathrm{x}}^2}}={\left(9^{{16\mathrm{x}}^2}\right)}^{1/2}=9^{{16\mathrm{x}}^2\times \frac{1}{2}}$$$$=9^{{8\mathrm{x}}^2}$$

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