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Question Number 22661 by ajfour last updated on 21/Oct/17

Commented by ajfour last updated on 21/Oct/17

$Q . 22657 (s o l u t i o n; h e r e b e c o z$ $(i m a g e s f r o m m y c e l l p h o n e$ $g e t s u p l o a d e d o n l y a s n e w$ $q u e s t i o n, a n d r a r e l y a s a n s$ $o r c o m m e n t) .$
	Answered by ajfour last updated on 21/Oct/17

	$\frac{1}{u_{1}} = \frac{1}{f} - \frac{1}{3 u_{1}} a n d u_{1} - v_{1} = D$ $\frac{1}{u_{2}} = \frac{1}{f} - \frac{1}{6 u_{2}} a n d u_{2} - v_{2} = D + 15$ $s o f = \frac{3 u_{1}}{4} a n d f = \frac{6 u_{2}}{7}$ $(u_{2} - v_{2}) - (u_{1} - v_{1}) = 15$ $- 5 u_{2} + 2 u_{1} = 15$ $\Rightarrow - 5 \times \frac{7 f}{6} + 2 \times \frac{4 f}{3} = 15$ $o r - 19 f = 90$ $f = - \frac{90}{19} c m \approx - 4.74 c m .$
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