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Question Number 22730 by selestian last updated on 22/Oct/17
Commented by math solver last updated on 22/Oct/17
−1.weknowtanispositivein1stand3rdquadrant.sothereareinfinitevalueswhichwecantake.saywetake60degreeand240degree.
Commented by selestian last updated on 22/Oct/17
yesyouarerightthAnksigottheanswer
Answered by ajfour last updated on 22/Oct/17
letthesmalleranglebeθ1.0⩽θ1⩽πThenθ2=θ1+π⇒tanθ22=tan(θ12+π2)⇒tanθ22=−cotθ12⇒tanθ12tanθ22=−1.
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