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Question Number 22929 by selestian last updated on 24/Oct/17

Answered by ajfour last updated on 24/Oct/17

(A)  r(cot (A/2)+cot (B/2))=c  r(cot (B/2)+cot (C/2))=a  r(cot (C/2)+cot (A/2))=b  2b=a+c , so  2r(cot (C/2)+cot (A/2))=r(cot (A/2)+                                  +2cot (B/2)+cot (C/2))  ⇒   cot (C/2)+cot (A/2)=2cot (B/2)  For a triangle Σcot (A/2)=Πcot (A/2)  ⇒cot (A/2)cot (B/2)cot (C/2) −cot (B/2)                                            =2cot (B/2)  ⇒  cot (A/2)cot (C/2)=3  ⇒    cot (A/2)=3tan (A/2) .

(A)r(cotA2+cotB2)=cr(cotB2+cotC2)=ar(cotC2+cotA2)=b2b=a+c,so2r(cotC2+cotA2)=r(cotA2++2cotB2+cotC2)cotC2+cotA2=2cotB2ForatriangleΣcotA2=ΠcotA2cotA2cotB2cotC2cotB2=2cotB2cotA2cotC2=3cotA2=3tanA2.

Commented by selestian last updated on 24/Oct/17

sir plz send me the solution plz plz

sirplzsendmethesolutionplzplz

Commented by math solver last updated on 24/Oct/17

sir how you wrote the 1st 3 eq. ?  r(....)=a ..... ??

sirhowyouwrotethe1st3eq.?r(....)=a.....??

Commented by ajfour last updated on 24/Oct/17

diagram ? which part especialy  do i explain more ?

diagram?whichpartespecialydoiexplainmore?

Commented by selestian last updated on 24/Oct/17

thanks sir can you plZ xplain

thankssircanyouplZxplain

Commented by ajfour last updated on 25/Oct/17

see Q.23009

seeQ.23009

Commented by selestian last updated on 25/Oct/17

plz xplAin from the line for a triangle

plzxplAinfromthelineforatriangle

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