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Question Number 23739 by ajfour last updated on 04/Nov/17

Commented by ajfour last updated on 04/Nov/17

$$Ifsystemofpairofrodsshown$$$$isreleasedatrestwhen{\theta }_0={\varphi }_0=\frac{\pi }{4};$$$$find\varphi asafunctionof\theta alittle$$$$later(tillsmallerrodisincontact$$$$withthewall).Assumebearings$$$$andwallsurfacearefrictionless.$$$$Forconsideringfirstasimplercase,$$$$letitbeassumedthat\mathit{l}=\mathit{L}and$$$$\mathit{m}=\mathit{M}.$$

Commented by mrW1 last updated on 04/Nov/17

$$\mathrm{Lcos}\theta +\mathrm{lcos}\varphi =(\mathrm{L}+\mathrm{l})\cos {\theta }_0=\mathrm{constant}$$$$\Rightarrow \varphi ={\cos }^{-1}[(\frac{\mathrm{L}}{\mathrm{l}}+1)\cos {\theta }_0-\left(\frac{\mathrm{L}}{\mathrm{l}}\right)\cos \theta ]$$

Commented by ajfour last updated on 05/Nov/17

$$thankyousir.$$

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