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Question Number 23759 by k Student last updated on 05/Nov/17

Commented by k Student last updated on 05/Nov/17

$$pleasesolveit$$

Commented by ajfour last updated on 05/Nov/17

Commented by ajfour last updated on 05/Nov/17

$$I_{cm}=m_1{r}_1^2+m_2{r}_2^2$$$$=m_1{\left(\frac{m_{2}r}{m_1+m_2}\right)}^2+m_2{\left(\frac{m_{1}r}{m_1+m_2}\right)}^2$$$$=\frac{m_1{m}_2{r}^2}{(m_1+m_2)}option\left(1\right).$$

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