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Question Number 24631 by tawa tawa last updated on 23/Nov/17

Answered by ajfour last updated on 23/Nov/17

$$F_{max}={ma}_{max}=m{\omega }^{2}A=kA$$$$=m{\left(\frac{2\pi }{T}\right)}^{2}A$$$$=0.12\times \frac{4\times 9.86}{0.04}\times 0.085N$$$$=10N$$$$k=\frac{10}{0.085}=118N/m.$$

Commented by tawa tawa last updated on 23/Nov/17

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

Commented by tawa tawa last updated on 23/Nov/17

$$\mathrm{I}\mathrm{really}\mathrm{appreciate}\mathrm{sir}$$

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