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Question Number 25943 by tawa tawa last updated on 16/Dec/17

Answered by ajfour last updated on 16/Dec/17

$$frictionf=\mu N=\mu m_{P}g$$$$=0.5\times 10\times 10=50newtons$$$$m_{Q}g-T=m_{Q}a...\left(i\right)$$$$T-f=m_{P}a...\left(ii\right)$$$$adding\left(i\right)and\left(ii\right):$$$$m_{Q}g-f=(m_P+m_Q)a$$$$or150-50=25a$$$$commonacc.\mathit{a}=4m/s^2.$$$$T=f+m_{P}a$$$$=50+10\times 4=90newtons.$$$$its{m}_{Q}gthatcausesPandQ$$$$toaccelerate.$$

Commented by tawa tawa last updated on 16/Dec/17

$$\mathrm{Wow},\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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