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Question Number 26924 by Tinkutara last updated on 31/Dec/17

	Answered by mrW1 last updated on 31/Dec/17

	$k = s p r i n g c o n s t a n t$ $u = d e f o r m a t i o n o f s p r i n g u n d e r f o r c e$ $u_{2} = m a x . d e f o r m a t i o n o f s p r i n g a f t e r r e l e a s e$ $\frac{1}{2} {k u}^{2} - m_{A} g u = \frac{1}{2} {k u}_{2}^{2} + m_{A} {g u}_{2} . . . (i)$ ${k u}_{2} = m_{B} g$ $\Rightarrow u_{2} = \frac{m_{B} g}{k} = \frac{m g}{k}$ $(i) b e c o m e s$ ${k u}^{2} - 2 m g u = \frac{3 {(m g)}^{2}}{k}$ $\Rightarrow k^{2} u^{2} - 2 m g k u - 3 {(m g)}^{2} = 0$ $\Rightarrow (k u - 3 m g) (k u + m g) = 0$ $\Rightarrow k u = 3 m g$ $F + m_{A} g = k u = 3 m g$ $\Rightarrow F = 2 m g$ $A n s w e r (2)$
	Commented by mrW1 last updated on 31/Dec/17

	Commented by Tinkutara last updated on 31/Dec/17
	Thank you very much Sir! I got the answer.
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