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Question Number 28076 by Tinkutara last updated on 20/Jan/18

Commented by Tinkutara last updated on 20/Jan/18

Answer given is 3rd. Is the answer correct?

Answered by ajfour last updated on 20/Jan/18

$$Atomicwt.=2g/mol$$$$no.ofatoms=\frac{4g}{2g/mol}=2mol=2N_A$$$$no.ofneutrons=\frac{1}{1atom}\times 2N_{A}atoms$$$$=2N_A.$$

Commented by Tinkutara last updated on 20/Jan/18

Yes this is the same I got thanks but I wanted to confirm the answer.

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