Question and Answers Forum

All Questions      Topic List

Electrostatics Questions

Previous in All Question      Next in All Question      

Previous in Electrostatics      Next in Electrostatics      

Question Number 31436 by ajfour last updated on 08/Mar/18

Commented by ajfour last updated on 08/Mar/18

$$Twochargedsmallballsare$$$$suspendedbystringsoflength$$$$Landl.Findequilibriumangle\theta .$$

Commented by ajfour last updated on 08/Mar/18

Commented by ajfour last updated on 08/Mar/18

$$L\sin \alpha +l\sin \beta =r\cos \gamma$$$$L\cos \alpha -l\cos \beta =r\sin \gamma$$$$Fromabovetwoeqs.r,\gamma are$$$$determined.$$$$F=\frac{Qq}{4\pi {ϵ}_0{r}^2}$$$$T_1\cos \alpha =Mg+F\sin \gamma$$$$T_1\sin \alpha =F\cos \gamma$$$$\Rightarrow \tan \alpha =\frac{F\cos \gamma }{Mg+F\sin \gamma }$$$$similarly$$$$\tan \beta =\frac{F\cos \gamma }{mg-F\sin \gamma }$$$$\Rightarrow \theta ={\tan }^{-1}\left[\frac{\frac{F\cos \gamma }{Mg+F\sin \gamma }+\frac{F\cos \gamma }{mg-F\sin \gamma }}{1-\frac{F^2\cos {}^2\gamma }{(Mg+F\sin \gamma )(mg-F\sin \gamma }}\right].$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com